In Young's double slit experiment,the seventh | vedclass

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Question

(A) In Young's double slit experiment,the position of the $n^{th}$ maximum from the central maximum is given by the formula: $x_n = \frac{n \lambda D}

Vedclass · Accepted Answer

$\frac{\lambda_1}{\lambda_2}$

Vedclass · Answer

(A) In Young's double slit experiment,the position of the $n^{th}$ maximum from the central maximum is given by the formula: $x_n = \frac{n \lambda D}{d}$.For the seventh maximum $(n=7)$ with wavelength $\lambda_1$,the distance is $d_1 = \frac{7 \lambda_1 D}{d}$.For the seventh maximum $(n=7)$ with wavelength $\lambda_2$,the distance is $d_2 = \frac{7 \lambda_2 D}{d}$.Taking the ratio of $d_1$ and $d_2$:$\frac{d_1}{d_2} = \frac{\frac{7 \lambda_1 D}{d}}{\frac{7 \lambda_2 D}{d}} = \frac{\lambda_1}{\lambda_2}$.Thus,the correct option is $A$.

In Young's double slit experiment,the seventh maximum with wavelength ${\lambda _1}$ is at a distance $d_1$ from the central maxima,and the same maximum with wavelength ${\lambda _2}$ is at a distance $d_2$. Then the ratio $d_1/d_2$ is:

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